operator+,-,*,/,%(std::chrono::duration)
| template< class Rep1, class Period1, class Rep2, class Period2 > typename std::common_type<duration<Rep1,Period1>, duration<Rep2,Period2>>::type |
(1) | |
| template< class Rep1, class Period1, class Rep2, class Period2 > typename std::common_type<duration<Rep1,Period1>, duration<Rep2,Period2>>::type |
(2) | |
| template< class Rep1, class Period, class Rep2 > duration<typename std::common_type<Rep1,Rep2>::type, Period> |
(3) | |
| template< class Rep1, class Rep2, class Period > duration<typename std::common_type<Rep1,Rep2>::type, Period> |
(4) | |
| template< class Rep1, class Period, class Rep2 > duration<typename common_type<Rep1,Rep2>::type, Period> |
(5) | |
| template< class Rep1, class Period1, class Rep2, class Period2 > typename std::common_type<Rep1,Rep2>::type |
(6) | |
| template< class Rep1, class Period, class Rep2 > duration<typename common_type<Rep1,Rep2>::type, Period> |
(7) | |
| template< class Rep1, class Period1, class Rep2, class Period2 > typename common_type<duration<Rep1,Period1>, duration<Rep2,Period2>>::type |
(8) | |
Performs basic arithmetic operations between two durations or between a duration and a tick count.
rhs number of ticks subtracted from the lhs number of ticks after conversion.d to one whose rep is the common type between Rep1 and Rep2, and multiples the number of ticks after conversion by s.d to one whose rep is the common type between Rep1 and Rep2, and divides the number of ticks after conversion by slhs after conversion by the tick count of rhs after conversion. Note that the return value of this operator is not a duration.d to one whose rep is the common type between Rep1 and Rep2, and creates a duration whose tick count is the remainder of the division of the tick count, after conversion, by s.[edit] Parameters
| lhs | - | duration on the left-hand side of the operator |
| rhs | - | duration on the right-hand side of the operator |
| d | - | the duration argument for mixed-argument operators |
| s | - | tick count argument for mixed-argument operators |
[edit] Return value
Assuming that CD is the function return type and CR<A, B> = std::common_type<A, B>::type, then:
[edit] Example
#include <chrono> #include <iostream> int main() { // simple arithmetic std::chrono::seconds s = std::chrono::hours(1) + 2*std::chrono::minutes(10) + std::chrono::seconds(70)/10; std::cout << "1 hour + 2*10 min + 70/10 sec = " << s.count() << " seconds\n"; // difference between dividing a duration by a number // and dividing a duration by another duration std::cout << "Dividing that by 2 minutes gives " << s / std::chrono::minutes(2) << '\n'; std::cout << "Dividing that by 2 gives " << (s / 2).count() << " seconds\n"; // the remainder operator is useful in determining where in a time // frame is this particular duration, e.g. to break it down into hours, // minutes, and seconds: std::cout << s.count() << " seconds is " << std::chrono::duration_cast<std::chrono::hours>( s ).count() << " hours, " << std::chrono::duration_cast<std::chrono::minutes>( s % std::chrono::hours(1) ).count() << " minutes, " << std::chrono::duration_cast<std::chrono::seconds>( s % std::chrono::minutes(1) ).count() << " seconds\n"; }
Output:
1 hour + 2*10 min + 70/10 sec = 4807 seconds Dividing that by 2 minutes gives 40 Dividing that by 2 gives 2403 seconds 4807 seconds is 1 hours, 20 minutes, 7 seconds